Equations of a Line

Question 1

Find the equation of a line passing through the points
( 1, -9 ) and ( -3, -2 ).

Solution

To find the equation of a line passing through the points
( 1, -9 ) and ( -3, -2 ), we must first determine the slope of the line. Using the slope formula, the slope of the line is,

   m = ( y2 - y1 ) / ( x2 - x1 )
 m
= ( -2 - ( -9 ) ) / ( -3 - 1 )
 m = ( -2 + 9 ) / ( -3 - 1 )
 m = -7/4
 

Now, we simply plug in the value of the slope and the x and y values of either point into the point-slope equation.

   y - y1 = m ( x - x1 )
 y - ( -9 ) = ( -7/4 )( x - 1 )
 y + 9 = ( -7/4 )( x - 1 )
 

Hence, the equation of the line is,

   y + 9 = ( -7/4 )( x - 1 )  

If we had used the second point, then the equation would look like this:

   y - y1 = m ( x - x1 )
 y - ( -2 ) = ( -7/4 )( x - ( -3 ) )
 y + 2 = ( -7/4 )( x + 3 )
 

Thus, the equation of the line would be,

   y + 2 = ( -7/4 )( x + 3 )  

Although this equation looks different from the previous one, they are, in essence the same equation. To prove this we will convert each equation into slope-intercept form. By doing this, we should come up with the same equation. Converting the first equation would give us,

   y + 9 = ( -7/4 )( x - 1 )
 y + 9 = ( -7/4 )x + 7/4
 y = ( -7/4 )x + 7/4 - 9
 y = ( -7/4 )x + 7/4 - 36/4
 y = ( -7/4 )x - 29/4
 

Converting the second equation would give us,

   y + 2 = ( -7/4 )( x + 3 )
 y + 2 = ( -7/4 )x - 21/4
 y = ( -7/4 )x - 21/4 - 2
 y = ( -7/4 )x - 21/4 - 8/4
 y = ( -7/4 )x - 29/4
 

As you can see, both equations, when converted into slope-intercept form, are identical. Therefore, any one of the three equations given above would be a correct answer to this problem.



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